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*Stealth*
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Topic: Extra credPosted: 01 March 2007 at 7:48pm |
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John is now twice as old as he was when Mary was three years older than he is now, but he is only half as old as Mary is at present. Now, how old are they?
Any one got any ideas, a friend just sent to this me seeing if I could come up with something... I for one am blank. |
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BARREL BREAK
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Posted: 01 March 2007 at 7:59pm |
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Trick question, no ages are given in the problem.
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procarbinefreak
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Posted: 01 March 2007 at 8:00pm |
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mary is 12 and john is 6
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*Stealth*
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Posted: 01 March 2007 at 8:02pm |
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same thing I was thinking, how did you come about the answer? |
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hoginds24
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whos the ph00l now?!?!?! Joined: 23 February 2003 Location: Tiny Status: Offline Points: 1872 |
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Posted: 01 March 2007 at 8:03pm |
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No.
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SSOK
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Posted: 01 March 2007 at 8:06pm |
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Mary is twice the age of John. I was using the lowest numbers as possible when I started. John was two and Mary was one, but I changed Mary to 5 because she was three years older than john, and since John is half marys age that would make him 2 1/2. But 12 and 6 probably works. Mary is twice as old as John. Thats it...
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Farcry0092
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Posted: 01 March 2007 at 9:47pm |
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M=6 J=3 solution= j=.5m (plug this into below problem) &nbs p; &nbs p; jx2=j+3 j(.5m)=.5m+3 m=.5m+3 .5m=3 m=6 plug M(6) into one of the original problems: j=.5(6) i think this might be right but im not sure feel free to correct me if im wrong
Edited by Farcry0092 - 01 March 2007 at 9:48pm |
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Jack Carver
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Posted: 01 March 2007 at 9:50pm |
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Ok I think I found how do to it mathematically:
j = John's current age m = Mary's current age We know john is half Mary's age 2*j = m and that also means the difference in age is equal to John's current age j = m-j Now since "John is twice as old as he was when Mary was three years older than he is now" (most confusing thing evar) So John is twice as old as john-young j = 2(j-young) And j-young is Mary's age at that point (j+3), minus the difference in age (j). j-young = j+3-j = 3 plug it back in to j=2(j-young) to get: j = 2(3) So John's current age is 6, Mary is twice that, 12. There's probably an easier way to state that, but the key lies in that the difference in age is John's age, and that never changes. Now that that's solved, here's a riddle:
Edited by Jack Carver - 01 March 2007 at 9:52pm |
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Farcry0092
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Posted: 01 March 2007 at 9:55pm |
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hmmmmm if what you did, jack, is right, wanna help me figure out what i did wrong?
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Jack Carver
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Posted: 01 March 2007 at 10:01pm |
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I think it was where you took
jx2=j+3 John is only half of Mary's age right now. Back then, when Mary was 3 years older than John's current age, she was actually 3 times his age. As 2 kids get older, their ages become closer and closer together by percentage (multiplication), but always the same amount of years by subtraction. |
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procarbinefreak
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Posted: 01 March 2007 at 10:03pm |
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i did guess and check
until i found it. |
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Farcry0092
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Posted: 01 March 2007 at 10:05pm |
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thanks for that. your right i went back and looked and i was wrong. |
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Dye Playa
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Posted: 01 March 2007 at 10:07pm |
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i'm not even going to attempt it. my brain hurts looking at the math you guys are doing.
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Farcry0092
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Posted: 01 March 2007 at 10:15pm |
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^^if your in at least algebra one, its not that hard. i just messed up setting the problem up. |
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Monk
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Posted: 01 March 2007 at 10:18pm |
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I and We?
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choopie911
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Posted: 01 March 2007 at 10:27pm |
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There are no ages given, so there is no point of reference. Any answer found would just be a possible solution at some point in their life, and pure speculation.
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Jack Carver
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Posted: 01 March 2007 at 10:37pm |
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Wrong.
2 variables, 2 equations. 1 and only 1 answer. |
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choopie911
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Posted: 01 March 2007 at 10:41pm |
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example: This number is twice as much as it was when another number was the same, plus three. This number is half of the same number now, whats the number? You've got nothing to work with.... |
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jerseypaint
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Posted: 01 March 2007 at 10:44pm |
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Shes too old for him.
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Monk
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Posted: 01 March 2007 at 10:57pm |
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You still have two variables. number and another number. This is alittle more than algebra. This is more like pre-calculus. |
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