PSI to Depress Pin
Printed From: Tippmann Paintball
Category: Paintball Equipment
Forum Name: Gun Maintenace and Repair
Forum Description: Important info for keeping your marker in top shape
URL: http://www.tippmannsports.com/forum/wwf77a/forum_posts.asp?TID=163801
Printed Date: 10 January 2026 at 11:19pm Software Version: Web Wiz Forums 12.04 - http://www.webwizforums.com
Topic: PSI to Depress Pin
Posted By: Walking Stick
Subject: PSI to Depress Pin
Date Posted: 21 January 2007 at 2:27am
Let's say a Model 98 is running on a constant, regulated airflow of 500 pounds per square inch. What amount of force, in pounds, is required to depress the valve pin fully (0.25")? I stacked weights on CVX's with HP valve springs and themselves require 8 or 15 pounds to depress. For simplicity's sake, let's just say the valve seat's area is 0.25 inches. Is 500psi a constant, with the pin requiring 500 pounds of force to be depressed? I don't think this is so. Is 500psi a ratio, where 500 pounds:1 inch would translate to 125 pounds:0.25 inch? Possible, but I don't think it'd be this simple. Is it an inverse relationship? 4x smaller area requiring 4x greater force? Hey, I'm tossing out all possibilities here.
I am not familiar with fluid dynamics, so any intelligent help would be appreciated. Any associated formulas, calculations or factors would be beneficial, so I could figure other figures out for myself, as well. Thank you. (If it fails here I'll just e-mail Tippmann Tech directly.)
------------- Model98.org
|
Replies:
Posted By: Bruce A. Frank
Date Posted: 21 January 2007 at 3:15am
|
The poppet valve is round so its area is not 1/4 sq inch. The area of a circle is: 
So the head of the poppet valve would have an area of .0625". (.25 X .25 = .0625 sq in.)
.0625 sq in X 500 psi = 32.25 pounds of force to depress the pin.
Stick, this is Middle School math.
-------------

|
Posted By: Walking Stick
Date Posted: 21 January 2007 at 3:35am
I know the area of a circle, I just wanted to make it simpler.
I originally did that, finding the area in inches and multiplying by 500, but after finding out the valve spring requires 8 or 15 pounds of force, I doubted myself. I thought it would be a much greater force and tried to find other ways, thinking about airflow, areas, etc.
Funny thing is, I stumped other tech forums and two of my friends who are past their second year in mechanical engineering!
Thanks for slapping me and reminding me to KEEP IT SIMPLE!
------------- Model98.org
|
Posted By: cmts58
Date Posted: 21 January 2007 at 3:48am
wrong time for so much thinking...blahhhhhhhhhh
------------- tippmann 98c
dop pro seal
expansion chamber
vertical adapter
dop double trigger
cyclone feed
|
Posted By: Walking Stick
Date Posted: 21 January 2007 at 4:49am
|
WAIT A MINUTE! See this is where I went wrong!
500 x 0.25 x 0.25 = 31.25 is what I did initially, but what about pi?
500 x 3.14 x 0.25 x 0.25 = 98.125 is when I inputted pi.
Two other sources did give me your answer Bruce A. Frank (about 10 others had no clue or vague guesses) so I want to believe you. But why did I multiply the squared radius by pi to find the area of the circle when you didn't?!
You're right cmts58, it's too darn late for this stuff...
------------- Model98.org
|
Posted By: DeTrevni
Date Posted: 21 January 2007 at 5:33am
|
...
This thread is too intelligent for 98.9% of this forum. Good luck with that.
------------- Evil Elvis: "Detrevni is definally like a hillbilly hippy from hell"
|
Posted By: Shadowminion
Date Posted: 21 January 2007 at 9:55am
|
Once you figure out the area of the circles involved , you enter into physics , Ie: Mass , velocity , Kinetic energy and such .
The rear hammer is propelled forward by the mainspring when the trigger is pulled (factor in friction , strength of mainspring , mass of rear bolt , and the impact energy when it strikes the CVX valve ) .
Oppossing this is the pressure behind the CVX valve poppet , the spring force on the poppet valve .
The main factors that are easy enough to control are with the rear bolt , its velocity (either by changing the mainspring , or reducing the friction associated with movement of the rear bolt , and sometimes the equivalent mass of the rear bolt) .
Kinetic energy stored in the mainspring is transferred to the valve through the rear bolt . With a straight mechanical set-up , the laws of physics dictate the amount of time and degree of being fully opened for the CVX valve . Simple hydraulic principles apply . For an example a 1" control valve supplying supplying 100 PSI to a 10" Cylinder will enable the 10" cylinder to lift approximately 1800 pounds , this doesnt sound correct until you figure the areas involved , but do the math , I did it real quick off the top of my head , but it should be close .
I dont know any of the formulas , but with a well based understanding of the principals involved , the exact formulae arent required (unless you are a fluid mechanics engineer) .
If you desire to change any of the characteristics of timing of the CVX valve , it cant feasibly be done without electronics , then you can mess with parameters such as dwell , and that would require an entirely different configuration of gas management (Bye-Bye CVX valve ! , Hello Solenoid ! ) .
Hope this points you in the right direction .
------------- SL68-II , micro honed and polished .688" bore . Tuff Enuf .
Widowmaker , under construction
|
Posted By: tallen702
Date Posted: 21 January 2007 at 11:15am
Shadowminion wrote:
Once you figure out the area of the circles involved , you enter into physics , Ie: Mass , velocity , Kinetic energy and such .
The rear hammer is propelled forward by the mainspring when the trigger is pulled (factor in friction , strength of mainspring , mass of rear bolt , and the impact energy when it strikes the CVX valve ) .
Oppossing this is the pressure behind the CVX valve poppet , the spring force on the poppet valve .
The main factors that are easy enough to control are with the rear bolt , its velocity (either by changing the mainspring , or reducing the friction associated with movement of the rear bolt , and sometimes the equivalent mass of the rear bolt) .
Kinetic energy stored in the mainspring is transferred to the valve through the rear bolt . With a straight mechanical set-up , the laws of physics dictate the amount of time and degree of being fully opened for the CVX valve . Simple hydraulic principles apply . For an example a 1" control valve supplying supplying 100 PSI to a 10" Cylinder will enable the 10" cylinder to lift approximately 1800 pounds , this doesnt sound correct until you figure the areas involved , but do the math , I did it real quick off the top of my head , but it should be close .
I dont know any of the formulas , but with a well based understanding of the principals involved , the exact formulae arent required (unless you are a fluid mechanics engineer) .
If you desire to change any of the characteristics of timing of the CVX valve , it cant feasibly be done without electronics , then you can mess with parameters such as dwell , and that would require an entirely different configuration of gas management (Bye-Bye CVX valve ! , Hello Solenoid ! ) .
Hope this points you in the right direction . |
All very true, but the CVX valve wouldn't necessarily need to go bye-bye. The E-bolt, for example, still had the ability to change the dwell of the CVX valve but through exterior interaction rather than internal timing itself. While a solenoid would still be needed to maintain pressure over specific time, it isn't necessary to replace the entire valve itself. Now, if you were looking to change the timing of the valve internally, then yes, you'd either have to rely on a solenoid to regulate the rate of flow at a constant pressure, OR, find some mechanical (servo motor possibly?) method of maintaining an opening for a certain period of time at a constant pressure. Mind you, servos aren't as fast as a solenoid and drain far more power. God, it is way too early in my day to be discussing all of this.
------------- <Removed overly wide sig. Tsk, you know better.>
|
Posted By: Bruce A. Frank
Date Posted: 22 January 2007 at 2:18am
|
Apparently middle school math is beyond me. I was so intent on one part I DID forget about pi. Trying to get this stuff on the screen diverts my attention.
It should by .0625 X p = .19625
Then 500 X .19625 = 98.125 pounds
-------------

|
Posted By: Monk
Date Posted: 22 January 2007 at 9:16am
The force of the spring is only half the story. You have to factor in the inertia of the bolt its self. It may be pushed by 10 pounds of force, but it may hit with 100 pounds of force.
Ill do the math later tonight, and get it posted on the forum.
|
Posted By: Shadowminion
Date Posted: 22 January 2007 at 9:37am
|
Monk ,,, thats the Mass , Velocity and Impact energy components of the mix . The math is WAY out of my league .
What Tallen said is very true , I cant venture to hazard a guess about the things which he speaks of for I have no experience with solenoids or servos as they relate to paintball in any relevant manner .
However,,, I can think of a solenoid/Cam configuration that would be able to control dwell on a CVX valve , but it would need to be totally custom built .
------------- SL68-II , micro honed and polished .688" bore . Tuff Enuf .
Widowmaker , under construction
|
Posted By: tallen702
Date Posted: 22 January 2007 at 11:06am
Posted By: Bruce A. Frank
Date Posted: 22 January 2007 at 11:14pm
Posted By: Walking Stick
Date Posted: 22 January 2007 at 11:57pm
|
No need for me to worry about the hammer, drive spring, mass, etc. because I don't plan on using any.
I hate electronic markers and the length of the mechanical Model 98, so I'm going to attempt to make it pneumatic (or pneumatic/mechanical if I need some leverage ). Fear not, for it will still be a Tippmann at heart! Just some changes to the M98's aesthetics and how the valve's airflow is triggered, actuated and discharged. If all goes right, I'll have the "Speedball" Tippmann people want, and I'll post my project/results initially at Model98.org.
I'll have to look into rotary valves, even if just for the knowledge. I appreciate everyone's help and input, thank you. I'll see you around and keep you informed in the months to come!
------------- Model98.org
|
Posted By: tallen702
Date Posted: 23 January 2007 at 6:34pm
Bruce A. Frank wrote:
If you are not pressing directly against air pressure as a poppet valve does the concept is easy to impliment. There are mechanical rotary valves I have bought that require virtually no actuation pressure to release thousands of pounds of gas pressure...all mecanical. THe valves weren't inexpensive, but were in the $25 range 12 years ago.
Quarter inch ID line with dual Palmer Stabilizers gave me more than enough flow for a similar idea I tried a couple of years ago. |
The design I'm currently running with is a slide-gate valve. The slide back and forth to open and close the path of the air flow doesn't need to be very large, nor does it need to be very thick. I plan on actuating it using a solenoid to push air to the front and back of the slide to move it. The bolt will be tied in to the gate valve so that the solenoid is the only actuator you need. It is based off the same principle of the matrix bolt-sail design, but without the bolt and valve assembly being one solid piece (which required such a large top tube) I'm trying to work everything out so that the solenoid is housed in the grip with the board, and the body is only as wide as the 07 ego and shorter in length due to the minimal bolt travel and absence of a valve chamber.
------------- <Removed overly wide sig. Tsk, you know better.>
|
|